I am interested in LLM programs in CA, especially the LLM programs in UC Hastings, in order to be eligible to sit for the CA bar exam.

As you may know, new "Guidelines" of CA bar for applicants educated outside of US are in effect this year, According to Guideline 1.3 it is required that all course work for the LLM degree must be graded using the standards the law school uses in grading course work of students in its J.D. degree program. This means that the same grading standard as JD program (so-called JD Curve) should be applied to the grading of LLM students to be eligible for CA bar exam.

However, it appears that UC Hastings (including Santa Clara) grades its LLM students using the grading scale different from the JD program. Thus, I wish to know if there is option in UC hastings to be graded by the same standard as JD.

I sent e-mail to UC Hastings two times, but they have not replied till now. So, is there anybody who knows about it, please let me know.

Thanks.

This post unfortunately contains inaccurate information. First, UC Hastings has no Santa Clara campus. Second, it implies, quite wrongly, that graduates from UC Hastings' LL.M. program cannot qualify to take the Bar in California. Nothing could be further from the truth. Every exam date, LL.M.s who have graduated with an LL.M. in U.S. Legal Studies from UC Hastings qualify to take the Bar based on the coursework they have completed at Hastings. The Guidelines speak in terms of application of standards only and do not speak to a specifically enumerated grading scale. I do not know whether by your post you are intentionally trying to discredit UC Hastings (I hope not!), but at the very best you are spreading misinformation. This is sad, as the LL.M. Program at Hastings is a top-notch program with many satisfied students.

Mmmm, I think Ipeg was simply trying to gather some information!

Overselling a degree/program is also spreading misinformation. Don't know much about UC Hastings and student satisfaction, but "top-notch program" seems a little strong.